5t^2+50t=-125

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Solution for 5t^2+50t=-125 equation: 



5t^2+50t=-125

We move all terms to the left:

5t^2+50t-(-125)=0

We add all the numbers together, and all the variables

5t^2+50t+125=0

a = 5; b = 50; c = +125;
Δ = b2-4ac
Δ = 502-4·5·125
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-50}{10}=-5$

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